Computing Central Force Potential: Bound from |r| to Infinity

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Homework Help Overview

The discussion revolves around computing the potential for a central force defined by the equation F(r) = f(r)r, where r represents the magnitude of the position vector. The original poster seeks clarification on why the integral for potential V(r) is bounded from |r| to infinity, as mentioned in a reference.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand the bounds of the integral for potential energy and questions the reasoning behind choosing infinity as a limit. Another participant suggests that the potential is typically set to zero at infinity for simplicity. Additionally, the original poster raises a further question regarding the existence of potential for forces that depend on the position vector but not its magnitude.

Discussion Status

The discussion is ongoing, with participants exploring the implications of the integral bounds and the conditions under which potential exists for different forms of force. Some participants express confusion regarding the concepts being discussed, indicating that clarification is still needed.

Contextual Notes

There is an emphasis on understanding the conditions under which potential energy can be defined, particularly in relation to the nature of the force and its dependence on the position vector.

mystraid
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Hello,

I am trying to compute the potential for a central force of the form: F(r) = f(r)r
where r=|r|

Using the conservative force information, equation1 comes for potential V(r):

equation1: V(r) = [tex]\int[/tex] (-F(r))= [tex]\int[/tex] (-f(r) r)

In http://en.wikipedia.org/wiki/Central_force" it is stated that this integral is bounded from |r| to infinity. However I could not understand the reason.

Could someone help me?
Thanks..
 
Last edited by a moderator:
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Welcome to PF!

Hello mystraid! Welcome to PF! :wink:

It has to be bounded from |r| to somewhere

we can choose that somewhere to be anywhere, but it makes it simplest if we choose it to be ∞ (so the potential is always 0 at ∞). :smile:
 
Thank you for the reply tiny-tim.

And, I have another question. What if the function is dependent on the position vector r but not the magnitude of it?

So:

F(r) = f(r)r

Then is there any potential for such a force, and if so, under what conditions it exists?

Thanks
 
I'm sorry, I don't understand. :confused:
 
Me, too:smile:
 

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