Concentrated pressure drop in tube having 90 round bend

AI Thread Summary
To calculate the concentrated pressure drop in tubes with 90-degree and 180-degree bends, the equation dP (concentrated) = 1/2 * b * r * v^2 is used, where 'b' is the specific coefficient for concentrated pressure drop, 'r' is the liquid density, and 'v' is the fluid's average speed. Determining the value of 'b' is essential, and Crane Technical Paper No. 410 is recommended as a key resource for these coefficients. The user provided specific details about their setup, including mass flow rate, tube lengths, and diameters, but lacks access to the Crane paper. A suggestion was made to run calculations manually and to explore additional resources online for approximations. The discussion emphasizes the importance of understanding the calculations rather than relying solely on software.
alshourbagy
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Hi
i want to calculate the concentrated pressure drop in a tube having 90 round bend and other one having 180 round bend.
The equation that i know is:
dP (concentrated) = 1/2 * b*r*v^2
where:
b=specific coefficient for concentrated pressure drop
r = liquid density (kg/m³)
v = average speed of the fluid inside the tube (m/s)

My problem is how to determine b?

thanks
Moh
 
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One of the best sources of these factors is the Crane Technical Paper No. 410. If you don't have access to this book, let me know your line size and flow rate I can give you some approximate values.
 
many thanks for your kind help...unfortunately I have no access.
here is the info...
1st line:
water mass flow rate= 1 l/m
tube Length=36m
internal diameter= 12mm
external diameter= 15mm

2nd line is the same except for the length that is 41m.
The tube will be bending like in the image attached.
 

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My Crane TP 410 book is at work, but start with this link

http://www.pressure-drop.com/

Run a few cases. Then make sure you can do this by hand calculation and not depend on the computer !
 
Thanks alot...i will do it
 
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