Conduction - Heat Equation - Units Don't Add Up

AI Thread Summary
The discussion focuses on the challenges of applying the heat equation to inertia friction welds, specifically regarding unit consistency in heat input terms. The user, Chris, is trying to derive heating rates and temperature profiles but encounters a problem with the heat input being expressed in watts or watts/m² rather than the required watts/m³ for the equation. He clarifies that he has a non-homogeneous boundary condition and seeks confirmation on his approach. The conversation highlights the importance of ensuring consistent units in thermal analysis for accurate modeling. Ultimately, Chris is looking for guidance on correcting his formulation to align with the heat equation requirements.
chrissimpson
Messages
11
Reaction score
0
Conduction - Heat Equation - Units Don't Add Up!

Hi there

I have what I think/hope is a simple question:

I've been working on heat inputs and outputs in inertia friction welds and have managed to produce a net power term (W) as a function of time.

I now want to use that in the heat equation to come up with heating rates, temperature profiles and final cooling rates (these can then be related back to the final weld microstructure).

So, the equation I wish to use is:

ut-αuxx=(α/κ)*f(x,t) - a non-homogeneous pde

The problem I'm having with this is that my heat input term is in watts or watts/m^2, not watts/m^3. This is because my heat input is coming from one surface into a long/infinite length bar. When heat generation is in watts/m^3 you get consistent units of K/s throughout the equation. I don't!

Any ideas?

Cheers

Chris
 
Engineering news on Phys.org


I think that I may have made a mistake with my formulation of the problem; I actually have a non-homogeneous boundary condition, so:

ut=αuxx

with Neumann boundary conditions of:

ux(0,t)=Q/kA - with both sides having units of K/m

ux(L,t)=0


Does this seem like the correct way of looking at the problem?

Cheers

Chris
 
Posted June 2024 - 15 years after starting this class. I have learned a whole lot. To get to the short course on making your stock car, late model, hobby stock E-mod handle, look at the index below. Read all posts on Roll Center, Jacking effect and Why does car drive straight to the wall when I gas it? Also read You really have two race cars. This will cover 90% of problems you have. Simply put, the car pushes going in and is loose coming out. You do not have enuff downforce on the right...
I'm trying to decide what size and type of galvanized steel I need for 2 cantilever extensions. The cantilever is 5 ft. The space between the two cantilever arms is a 17 ft Gap the center 7 ft of the 17 ft Gap we'll need to Bear approximately 17,000 lb spread evenly from the front of the cantilever to the back of the cantilever over 5 ft. I will put support beams across these cantilever arms to support the load evenly
Thread 'Physics of Stretch: What pressure does a band apply on a cylinder?'
Scenario 1 (figure 1) A continuous loop of elastic material is stretched around two metal bars. The top bar is attached to a load cell that reads force. The lower bar can be moved downwards to stretch the elastic material. The lower bar is moved downwards until the two bars are 1190mm apart, stretching the elastic material. The bars are 5mm thick, so the total internal loop length is 1200mm (1190mm + 5mm + 5mm). At this level of stretch, the load cell reads 45N tensile force. Key numbers...
Back
Top