Confirm my answers on Oscillating Springs?

AI Thread Summary
The discussion revolves around solving problems related to oscillating springs, specifically finding speed, acceleration, and time for a block at a distance from the equilibrium position. For problem 12, the user calculated the speed as approximately 0.1984 m/s after converting units correctly. In problem 13, they questioned the use of the maximum acceleration equation, indicating uncertainty about its applicability at different positions. For problem 14, they attempted to find the time taken for the block to move to 2.5 cm but were unsure about their calculations and unit conversions. Overall, the thread seeks confirmation and assistance on these physics problems related to oscillating springs.
vtmvick7
Messages
2
Reaction score
0
confirm my answers on Oscillating Springs??

Can anyone confirm or adjust my answers for problems 12 and 14? Also can someone help me start on problem 13.. Thanks guys I really appreciate the help

Homework Statement



012
Find the speed of the block when it is 2.5 cm
from the equilibrium position.
Answer in units of m/s.

013
Find its acceleration at 2.5 cm from the equilibrium position.
Answer in units of m/s2.

014
Find the time it takes the block to move from
x = 0 to x = 2.5 cm.
Answer in units of s.

Homework Equations


M= 0.7kg
k= 14.7 N/m
A= 5cm
w= 4.58 rads/s
T= 1.37s

The Attempt at a Solution



#14: x(t) = 5cm Cos(4.58rads/s*(t))
t= (1/4.58 rads/s) cos^-1 (2.5cm/5cm) = 13.09s??
do I convert it to meters??

#12: E=1/2mv^2 + 1/2kx^2 = 1/2ka^2
1/2(.7)v^2 + 1/2(14.7)(.025m)^2 = 1/2(14.7)(.05m)^2
.35v^2=.0137
v=0.1984m/s
I changed the cm to m, I should have done this right??
 
Physics news on Phys.org


I think I solved #13.. would I use the equation

a = -w^2 * x?
 


I think that works but that is the equation for maximum acceleration. This means that equation might not always work for a problem such as this. Is acceleration always at maximum when it is half the distance from the equilibrium? (I don't know the answer to this)

I did this problem a different way.

https://www.physicsforums.com/showthread.php?t=397323
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top