Confirming Convection: Heat Escape Through Unlidded Containers

AI Thread Summary
Heat escape from an unlidded container primarily occurs through convection, as hot air is less dense than cold air and rises. While conduction and radiation also contribute to heat loss, convection is the dominant mechanism in this scenario. Infrared radiation plays a minor role unless the container's interior temperature is extremely high. Overall, convection is the key process for understanding heat loss in open containers. This confirms the initial inquiry about heat escape dynamics.
gem0688
Messages
37
Reaction score
0
Hi,

Just a quick question, I just want to check that i am on the right lines!

When heat escapes through the top of a container which does not have a lid, is that due to convection? i/e hot air is less dense than cold air, so rises.

Cheers

o:) Gemma o:)
 
Physics news on Phys.org
Out of conduction, convection and radiation, you are correct that convection would account for the majority of the heat loss. There will be a little due to IR radiation, but that won't account for much unless the interior of the container is red hot.
 
Cheers,

just wanted 2 make sure! :biggrin:

o:) Gemma o:)
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top