Conformal map to convert circle to a line

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Homework Help Overview

The discussion revolves around finding a conformal mapping that transforms a circle or ellipse into a line, specifically in the context of a problem from a physics course. Participants are exploring the implications of the mapping function z^2 + 1/z^2 and its modifications for different circle radii.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the effectiveness of the mapping function z^2 + 1/z^2 for flattening circles and consider how to adapt it for circles of different radii. There are suggestions to visualize the mapping by analyzing its effects on various boundary surfaces and specific complex numbers.

Discussion Status

The discussion is active, with participants providing insights into the mapping process and its geometric interpretations. There is acknowledgment of the simplicity of the approach once clarified, but no consensus or final solution has been reached.

Contextual Notes

Participants note that a line can be viewed as a circle passing through infinity, which adds a layer of complexity to the mapping discussion.

shehry1
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I need a conformal mapping that would map an ellipse or a circle to a line. I need this for the http://physics.indiana.edu/~berger/p506_fall2008/p506ps6.pdf" .

As far as I can understand, z^2 + 1/z^2 makes the geometry similar to that of a plane on the horizontal axis with a circle centered on the origin. I can use the method of images (I think) but I was thinking of another map that would flatten out the circle and keep that plane in its current form.

Not that it matters, I tried to tailor the homographic projection to my needs but couldn't get it to work.
 
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z^2 + 1/z^2 does flatten out the circle, if the circle has radius 1. You need to modify this map to flatten out a circle of radius a.

It is easiest to think about what the map does to each of the three boundary surfaces, independently; i.e., what happens to points on the real axis > a, on the imaginary axis > ia, and on the quarter-circle of radius a. If you can't visualize what happens, then try plugging in a complex number into the map to see where it goes (i.e., try x, iy, and ae^(it)).
 
Ben Niehoff said:
z^2 + 1/z^2 does flatten out the circle, if the circle has radius 1. You need to modify this map to flatten out a circle of radius a.

It is easiest to think about what the map does to each of the three boundary surfaces, independently; i.e., what happens to points on the real axis > a, on the imaginary axis > ia, and on the quarter-circle of radius a. If you can't visualize what happens, then try plugging in a complex number into the map to see where it goes (i.e., try x, iy, and ae^(it)).

Hmmm...seems very simple now that you have put it that way - guess that's the whole thing. Thanks a lot. Would try it as soon as I get the time
 
Also, keep in mind a line is just a circle passing throgh infinity. (In this geometry, I mean)
 

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