Confused - Pressure in a canister?

AI Thread Summary
The discussion revolves around calculating the pressure of a CO2 canister using the ideal gas law, resulting in a calculated pressure of 444 Bar, which contrasts sharply with the manufacturer's quoted pressure of 60 Bar. Participants consider the possibility that CO2 may not behave as an ideal gas under the given conditions, suggesting that the manufacturer’s figure could represent vapor pressure rather than total pressure. There is also mention of ensuring proper unit conversions, specifically from cm³ to m³, which was confirmed to be done correctly in the initial calculations. The conversation highlights a lack of clarity regarding the discrepancy between theoretical calculations and manufacturer specifications. Ultimately, the confusion remains about the accurate representation of CO2 pressure in the canister.
b.kiddo44
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A manufacturer quotes a standard CO2 canister contains 16g of CO2 at a volume of 20cm^3.

So I need to calculate the pressure in the canister...

Using ideal gas law

P = nRT/V
n = 0.364mol (16 of co2)
R = 8.314 J/Kmol (universal gas constant)
T = 294k (gas is at room temp 21 deg C)
V = 20cm3 (volume of canister as quoted)

P = 444 Bar

However the manufacturer quotes the canister pressure to be 60Bar! This seems a bit more realistic to me but I've no idea how this could be the case.

Any thoughts to clear up the confusion?
 
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Its must be cubic meter.Convert 20 cm3 to meter3
 
Good point, but I already did the conversion to m^3 in the calculation to give 444Bar.
 
I don't know chemical very well but maybe there's another formula to calculate pressure.Maybe CO2 supposed to be non-idel gas.
Your equation seems correct.
 
hum, I don't think it matters if the gas is 'ideal' or not. The manufacturer quoting 16g of CO2 in a 20cm^3 canister stored at room temperature. I'm confused as to where the 60 Bar quote comes from.
 
Perhaps the CO2 is not all a gas under pressure and the pressure is the vapor pressure at a given temperature.
 
You wrote it isn't it ?
 
Theres only two option.First option this is not an idel gas.Ideal gas make the equation simpler but maybe there's another type of equation which I said before.
Second think As you said its not 60 bar

Theres no other option cause our solution is correct.
 
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