Confusion about bound surface current of a cube

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 2K views
kevinlee
Messages
1
Reaction score
0
If the magnetization vector is in the z direction, is the bound surface current of a cube always 0, since z cross z is 0, and x and -x cancels and y and -y cancels out?
 
Physics news on Phys.org
There will be bound surface currents on the X-Y outer surfaces that circulate around the cube.
This is just like the surface currents on a circular rod. The shape is just different.