Conservation laws in a curve spacetime

Magister
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Homework Statement



Given the energy-momentum tensor for a perfect fluid, what is the conservation laws that I can compute from

<br /> \nabla_b T^{ab}=0<br />

in a curve space-time.

Homework Equations



<br /> T^{ab}=(\rho + p) u^a u^b - p g^{ab}<br />

where p is the pressure and \rho is the density.

The Attempt at a Solution



I have already compute the geodesic equation, the equivalent to the equation of motion in a flat space-time.
I would like to know if there is any other conservation law to get. I supose that might be another one equivalent to the Navie-Strokes in flat space-time...

Thanks in advance
 
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Just write \nabla_b T^{ab}=0 explicitly in components (in terms of density, pressure and scale factor). You will get a conservation type eqn.
 
Dick said:
Just write \nabla_b T^{ab}=0 explicitly in components (in terms of density, pressure and scale factor). You will get a conservation type eqn.

In terms of scale factor? The problem is that they don't give me a metric. I don't know what to with the g^{ab} term...
 
I guess I was thinking of the problem in FRW background. Can you simplify anything w/o a metric? Not sure...
 
Well. I have already compute the equation of motion, in a curve space, from \nabla_b T^{ab}=0. So I suppose that there may be another one...
 
In general, there isn't any other conservation law, besides the covariant divergence of the energy-momentum tensor. However, if you have a space-time with a continuous symetry, there's a Killing field defined on the space-time, associated to that symettry. It can then serves to define another conservation law, in a similar way as a Noether current.
 
What about this:

<br /> <br /> \nabla_b T^{ab}=\nabla_b((\rho + p) u^a u^b) - g^{ab} \nabla_b p = 0<br /> <br />

where I have used \nabla_b g^{ab} = 0

<br /> u^a \nabla_b((\rho + p) u^b) + (\rho + p) u^b \nabla_b u^a -g^{ab} \nabla_b p = 0<br />

<br /> u_a u^a \nabla_b((\rho + p) u^b) + (\rho + p) u^b u_a \nabla_bu^a -g^{ab} u_a \nabla_b p = 0<br />

using the fact that \nabla_b (u_a u^a) = \nabla_b 1 \Leftrightarrow 2 u_a \nabla_b u^a = 0, I get

<br /> \nabla_b((\rho + p) u^b) = g^{ab} u_a \nabla_b p<br />

using this in the second equation I get

<br /> (\rho + p) u^b \nabla_b u^a = 0<br />

or

<br /> \nabla_u u^a = 0<br />

So I can saw that the equation of motion (a conservation law) can be derived from \nabla_b T^{ab}=0.
Am I wrong?

In general, there isn't any other conservation law, besides the covariant divergence of the energy-momentum tensor. However, if you have a space-time with a continuous symetry, there's a Killing field defined on the space-time, associated to that symettry. It can then serves to define another conservation law, in a similar way as a Noether current.

Just has I said above, they don't give me any metric, so I can't compute the Killing vectors.
 
Last edited:
From equation

<br /> <br /> \nabla_b T^{ab}=\nabla_b((\rho + p) u^a u^b) - g^{ab} \nabla_b p = 0,<br /> <br />

you get the following :

(1) <br /> \nabla_a ((\rho + p) u^a) = u^a \nabla_a p,<br />

AND :

(2) <br /> (\rho + p) u^a \nabla_a ( u^b) = (g^{ab} - u^a u^b) \nabla_a p.<br />

In the case of a pressureless gaz, p = 0, and you get the conservation of "matter" AND the geodesics equation :

(3) <br /> \nabla_a (\rho u^a) = 0,<br />

AND :

(4) <br /> u^a \nabla_a ( u^b) = 0.<br />There's no need of any particular metric to define conserved quantites with the Killing fields.
 
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