Conservation of angular momentum of space station

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SUMMARY

The discussion focuses on the conservation of angular momentum in a rotating space station modeled as a giant wheel with a radius of 100 meters and a moment of inertia of 5.00x108 kgm2. When 120 crew members, each averaging 65.0 kg, move from the rim to the center, the angular speed changes, affecting the apparent acceleration experienced by those at the rim. The relationship between initial and final angular speeds is established using the equation IiWi = IfWf, leading to the conclusion that Wi equals 1/5 of Wf.

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[SOLVED] Conservation of angular momentum

A space station shaped like a giant wheel has a radius of 1.00x10E2 m and a moment of inertia of 5.00x10E8 kgm2. A crew live on the rim and the staion is rotaing so that the crew experiences an apparent acceleration of 1g (1x9.81m/s2). When 120 people move to the center of the station for a union meeting, the angular speed changes. What apparent acceleration is experienced by the managers at the rim? Assume the average mass of a crew member is 65.0kg.



2. I think u have to use Li=Lf which is IiWi=IfWf
I=mr2 because its a disk




3. IiWi=IfWf(the group on the rim)+If2Wf2(group at the center)
the group at the centers r=0 so I=0 so that is eliminated
m(total)r2Wi=m(rim)r2Wf
I put in my masses and my radius and solved for Wi=1/5Wf

don't know what to do know or if that is even right please help!
 
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From the given data find the mass and velocity ( using m*v^2/r = g) of the space station. Using Wi=1/5Wf find the final velocity. From that find apparent g.
 

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