Conservation of energy relativity problem

AI Thread Summary
The discussion revolves around a physics problem involving the conservation of energy and mass-energy equivalence. Participants clarify that the energy obtained from converting 5 grams of mass can be equated to gravitational potential energy using the formula E=mc^2 and Mgh. There is some confusion regarding the use of kinetic energy formulas, but it is established that the correct approach is to use mass-energy equivalence. The original poster ultimately finds clarity after reviewing their textbook. The conversation highlights the importance of understanding fundamental physics equations in solving energy-related problems.
hibiscus23
Messages
5
Reaction score
0
Hi could someone please help me with this question. I don't know where to start. :rolleyes:

A certain amount of energy is obtained from conversion of 5.00 grams of mass. How much mass could this energy raise to a height of 96 m?
 
Physics news on Phys.org
Hi,

Use conservation of energy. The energy produced in the conversion (which you can caluculate by the most famous equation in physics) is equal to the gravitational potential energy. The only thing you don't know is the mass of the object that is raised to 96m.
 
um...

so it's 1/2mv^2 = mgh?
how would i get v?

If i use conservation of energy, then I don't have to use E=mc^2?

:confused:
 
You use mc^2=Mgh. mc^2 is still energy.
 
hibiscus23 said:
so it's 1/2mv^2

Is that the most famous equation in all of physics?

Nooooooo

C'mon, think Einstein.
 
thanks...i actually realized how to do it when i looked through the chapter again...
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Thread 'A bead-mass oscillatory system problem'
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame? I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...
Back
Top