Conservation of Energy: Spring onstant

AI Thread Summary
The discussion focuses on calculating the spring constant of a basketball dropped from a height of 3 cm, which compresses 0.015 m upon impact. The potential energy of the ball at the drop height is determined using the formula mgh, where m is the mass, g is the acceleration due to gravity, and h is the height. This energy is converted into elastic potential energy, represented by (1/2)kx^2, where k is the spring constant and x is the compression distance. By equating the gravitational energy to the elastic potential energy, the spring constant can be solved. The conservation of energy principle is central to the problem-solving process.
yomii
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Homework Statement


if a basketball of mass=5kg is dropped from a height of 3 cm hits the ground and it compresses 0.015m then what is the spring constant
 
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yomii said:

Homework Statement


if a basketball of mass=5kg is dropped from a height of 3 cm hits the ground and it compresses 0.015m then what is the spring constant
Please demonstrate effort and show one's work.

What is the potential energy of the ball with respect to the impact point?

What is the mechanical energy of a compressed spring in relation to spring constant and deflection?

Answer both questions and solve the problem.
 
yomii said:

Homework Statement


if a basketball of mass=5kg is dropped from a height of 3 cm hits the ground and it compresses 0.015m then what is the spring constant

use the conservation of energy.

Et1=Et1

all the the gravitational energy turns into elastic potential energy.

so Eg1 = Es2

mgh = (1/2)kx^2
 

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