Conservation of linear & angular momentum head on collision

AI Thread Summary
The discussion centers on a head-on collision between two cars that become locked together, resulting in a clockwise spin due to the offset collision point. Car A is traveling west at 10 mph and weighs 3000 lb, while Car B is traveling east at 15 mph and weighs 35000 lb. Participants emphasize the conservation of linear and angular momentum, noting that kinetic energy is not conserved in this scenario. The initial misunderstanding about the absence of angular momentum is clarified, highlighting that the perpendicular distance between the momentum vectors creates angular momentum. The conversation ultimately seeks to determine the angular velocity of the combined cars post-collision.
Ryan Gajdzisz
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Homework Statement


Two cars collide head on but offset from each others center of gravity. After the impact the two cars are locked together as one body. Due to the location of the collision point, the impact causes the two locked cars to spin clockwise.
Car A- traveling west going 10 mph, weighs 3000lb and the radius of gyration for this motion is 3 ft
Car B- traveling east going 15 mph, weighs 35000lb and the radius of gyration is 2.5 ft

The lateral distance between the center of gravity between the two cars is 1.6 ft and the longitudinal distance is 14 ft.
Determine the angular velocity of the 2 cars as they start to spin after the collision

Homework Equations


I know that the linear and angular momentum is conserved and that kinetic energy is not. I am not sure how the linear momentum and kinetic energy is converted into the angular momentum because there is no angular momentum to begin with.
Any help or push in the right direction would help

The Attempt at a Solution


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Hello Ryan, :welcome:

In PF your attempt at solution doesn't count: it's a picture of the problem statement. And PF rules/guidelines in fact don't allow to help when the poster doesn't show any own work.
In this case your
Ryan Gajdzisz said:
there is no angular momentum to begin with
is not correct. There is a perpendicular distance between the two momentum vectors, therefore there is angular momentum !
 
sorry I messed up when I was attaching my work here is what I did so far
 

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