Conservation of linear momentum collision

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SUMMARY

The discussion centers on a collision problem involving conservation of linear momentum. A 2.0 kg object moving at 3.0 m/s strikes a stationary 1.0 kg object. After the collision, the 2.0 kg object moves at 1.5 m/s at a 30-degree angle. The correct x-component of the velocity for the 1.0 kg object post-collision is determined to be 3.4 m/s, calculated using the momentum conservation equation m1v1i + 0 = m1v1f + m2v2f.

PREREQUISITES
  • Understanding of linear momentum conservation principles
  • Familiarity with vector components and trigonometry
  • Knowledge of basic physics equations related to collisions
  • Ability to perform calculations involving mass and velocity
NEXT STEPS
  • Review the principles of conservation of momentum in two-dimensional collisions
  • Learn how to resolve vectors into their x and y components
  • Study the effects of angles on momentum calculations
  • Explore additional collision types, such as elastic and inelastic collisions
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Students studying physics, particularly those focusing on mechanics and collision problems, as well as educators looking for practical examples of momentum conservation.

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Homework Statement


A 2.0 kg object moving along the x-axis at 3.0 m/s strikes a 1.0 kg object initially at rest. Immediately after the collision, the 2.0 kg object has a velocity of 1.5 m/s directed 30 degree from its initial direction of motion. What is the x-component of the veolcity of the 1.0 kg object just after the collision?


Homework Equations


pi = pf


The Attempt at a Solution


m1v1i + 0 = m1v1f + m2v2f
2(3) = 2(1.5cos30) + (1)vf
vf = 2.4 m/s

thats what i get, but the answer is 3.4 m/s. What am i doing wrong here?
 
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You are doing it correctly, calculate the vf again from your last equation it is coming out to be 3.4m/s. vf= 2(3)-2(1.5*\sqrt{3}/2) = 6 - 2.6 = 3.4
 

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