Conservation of Momentum in Women Jumping Off Flatcar

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The discussion focuses on applying the conservation of momentum principle to a scenario where N women, each with mass m, jump off a frictionless railway flatcar of mass M. When all women jump simultaneously, the final velocity of the flatcar can be calculated using the total momentum before and after the jump. If the women jump off one at a time, the final velocity of the flatcar can be expressed as a sum of terms, reflecting the sequential nature of the jumps. The initial momentum of the system is zero, and the final momentum must also equal zero, leading to the equations needed for both scenarios. Understanding the setup of these equations is crucial for solving the problem effectively.
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N women, each with mass m, stand on a railway flatcar of mass M. Tehy jump off one end of the flatcar with velocity u relative to the car. The car rolls in the opposite direction without friction.

A- What is the final velocity of the flatcar if all the women jump at the same time?

B- What is teh final velocity of the flatcar if they jump off one at a time? (The answer can be left in the form of a sum of terms)
 
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Use conservation of momentum.

P.S. Why women? Is it supposed to encourage creativity? :biggrin:
 
I know that it's conservation of momentum, but I don't know how to set up the starting equations or how to apply it.
 
S0C0M988 said:
I know that it's conservation of momentum, but I don't know how to set up the starting equations or how to apply it.

Hint: look at the women and the platform as a system. What is the initial momentum of the system? What is the final momentum of the system? In what relation must they be?
 
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