Conservation of Momentum Problem

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Homework Help Overview

The problem involves a collision between two balls, one moving and one at rest, and requires the application of conservation of momentum in a two-dimensional context. Participants are examining various statements related to the momentum before and after the collision.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Some participants discuss how to express conservation of momentum for both x and y components. Others question the dimensionality of the problem, clarifying that it is indeed two-dimensional.

Discussion Status

Participants are actively engaging with the problem, with some providing guidance on how to set up the equations for momentum conservation. There is a recognition of the need to analyze both axes separately, and some participants express understanding of the approach without reaching a definitive conclusion.

Contextual Notes

There is a mention of the initial momentum being entirely in the x-direction, which influences the setup of the equations for the final momentum. Participants are also reflecting on the implications of the equations presented in the problem statement.

jli10
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Homework Statement


A ball of mass [itex]m_1[/itex] travels along the x-axis in the positive direction with an initial speed of [itex]v_0[/itex]. It collides with a ball of mass [itex]m_2[/itex] that is originally at rest. After the collision, the ball of mass [itex]m_1[/itex] has velocity [itex]{v_1}_{x}{\hat{x}}+{v_1}_{y}{\hat{y}}[/itex] and the ball of mass [itex]m_2[/itex] has velocity [itex]{v_2}_{x}{\hat{x}}+{v_2}_{y}{\hat{y}}[/itex]. Consider the following five statements:

I) [itex]0=m_1{v_1}_x+m_1{v_2}_x[/itex]
II) [itex]m_1v_0=m_1{v_1}_y+m_2{v_2}_y[/itex]
III)[itex]0=m_1{v_1}_y+m_2{v_2}_y[/itex]
IV) [itex]m_1v_0=m_1{v_1}_x+m_1{v_1}_y[/itex]
V) [itex]m_1v_0=m_1{v_1}_x+m_2{v_2}_x[/itex]

Of these statements, the system must satisfy
a) I and II
b) III and V
c) II and V
d) III and IV
e) I and III

Homework Equations


[itex](mv)_i=(mv)_f[/itex]

The Attempt at a Solution


I've never learned how to incorporate conservation of momentum into a 3-d plane...
 
Last edited:
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jli10 said:

Homework Statement


A ball of mass [itex]m_1[/itex] travels along the x-axis in the positive direction with an initial speed of [itex]v_0[/itex]. It collides with a ball of mass [itex]m_2[/itex] that is originally at rest. After the collision, the ball of mass [itex]m_1[/itex] has velocity [itex]{v_1}_{x}{\hat{x}}+{v_1}_{y}{\hat{y}}[/itex] and the ball of mass [itex]m_2[/itex] has velocity [itex]{v_2}_{x}{\hat{x}}+{v_2}_{y}{\hat{y}}[/itex]. Consider the following five statements:

I) [itex]0=m_1{v_1}_x+m_1{v_2}_x[/itex]
II) [itex]m_1v_0=m_1{v_1}_y+m_2{v_2}_y[/itex]
III)[itex]0=m_1{v_1}_y+m_2{v_2}_y[/itex]
IV) [itex]m_1v_0=m_1{v_1}_x+m_1{v_1}_y[/itex]
V) [itex]m_1v_0=m_1{v_1}_x+m_2{v_2}_x[/itex]

Of these statements, the system must satisfy
a) I and II
b) III and V
c) II and V
d) III and IV
e) I and III

Homework Equations


[itex](mv)_i=(mv)_f[/itex]


The Attempt at a Solution


I've never learned how to incorporate conservation of momentum into a 3-d plane...

This looks like only 2-D to me?
 
write down the initial total momentum

then write down the final total momentum

then group the X components into one eqn and the Y components in another and see whether you can answer the question.

show your work and we can help
 
Whoops, sorry, I meant 2-d.
But I think I understand now... You just have to do conservation of momentum for each axis, right? Since the initial momentum is all in the x-direction, the final momentum for the y-components must sum to 0, which is shown in equation III. The initial x-momentum is given by [itex]m_1v_0[/itex], so the sum of components for the final x-momentum should be exactly that, given by equation V. Final answer (B).
 
Last edited:
jli10 said:
Whoops, sorry, I meant 2-d.
But I think I understand now... You just have to do conservation of momentum for each axis, right? Since the initial momentum is all in the x-direction, the final momentum for the y-components must sum to 0, which is shown in equation III. The initial x-momentum is given by [itex]m_1v_0[/itex], so the sum of components for the final x-momentum should be exactly that, given by equation V. Final answer (B).

That is correct.
 

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