Conserving Momentum in AB+C Reaction

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In the discussion on conserving momentum in the reaction AB + C = AC + B, participants focus on applying the principle of conservation of linear momentum to chemical reactions. They highlight that reactant molecules must collide with sufficient kinetic energy and the correct orientation for the reaction to occur, which implies momentum conservation during collisions. A proposed equation for momentum conservation is presented, indicating the relationship between the masses and velocities of the reactants and products. The importance of treating velocities as vector quantities is emphasized, ensuring accurate calculations. Overall, the discussion aims to clarify how to quantitatively demonstrate momentum conservation in this specific chemical reaction.
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Homework Statement



For the chemical reaction AB+C=AC+B establish the principle of conservation of linear momentum.

Homework Equations





The Attempt at a Solution



I am totally stuck.Please help a little so that I can proceed further.
 
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Going by the collision theory, each of the reactant molecules must have sufficient kinetic energy and must collide in the correct orientation for the reaction to proceed, so when the collisions take place, linear momentum is conserved.
 
Ok,I understand.But,how can I show that from the expression?It is a problem that came in an exam...so,I am to proceed quantitatively.
I do not want you to provide the solution...But,help me to develop the solution.
 
I am saying that this sort of approach:

(M_A + M_B)*V_AB + M_C*V_C = (M_A + M_C)*V_AC + M_B*V_B

That is for the chamical reaction we may establish the conservation of linear momentum in this way.

I hope I am correct.Please check.
 
Yeah, that looks all right. The velocities are vector quantities though.
 
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