Constant Acceleration in a Runner's Straight Line Progression?

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In the scenario where a runner covers half the remaining distance to the finish line every ten seconds, her acceleration does not have a constant magnitude. Initially, the runner travels a significant distance, but as she approaches the finish line, the distance covered in each interval decreases. This results in a change in speed that is not uniform, indicating variable acceleration. The runner's speed diminishes as she gets closer to the finish line, leading to a non-constant acceleration. Therefore, the acceleration is not constant due to the diminishing distances covered over time.
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a runner runs half the remaining distance to the finish line every ten seconds. she runs in a straight line and doesn't ever reverse her direction. does her acceleration have a constant magnitude? give a reason for your answer


i want just to know the situation
 
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Consider the parameters given. Take time intervals of ten seconds. Consider the distance traveled in the first ten seconds, the distance traveled in the next ten seconds, and so on. Then consider how her speed changes. That's your answer.
 
thanks a lot
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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