Constrained to move Horizontally

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Homework Statement



[PLAIN]http://img231.imageshack.us/img231/636/question2m.jpg

Homework Equations



v = \dot{r} \hat{r} + r\dot{\vartheta} \hat{\vartheta}

The Attempt at a Solution



\dot{r} = ?
\vartheta = 80°
v = 55mm/s

So I guess I just use the formula above.

v = \dot{r} \hat{r} + r\dot{\vartheta} \hat{\vartheta}

55² = \dot{r}² + rΘ'

And so you try and solve for \dot{r}

r'² = 55² - (r*Θ')²
r' = sqrt(55² - (r*Θ')²)

And then I get stuck. I am either missing something. Or not doing something right. I guess this isn't really r theta, it is more a conversion from r theta to x-y.

Not 100% sure how to do that though.

Cheers
 
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first you can write sevreal expresisons in tex as follows
\vec{v} = \dot{r} \hat{r} + r \dot{\vartheta}\hat{\vartheta}

so knowing theta and |v| you should be able to decompose v into components in the orthogonal directions \hat{r}, \hat{\vartheta}
 
I manage to get the question.

Thanks :D
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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