Continuity of the derivative of a decreasing differentiable function

Petek
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Homework Statement



To solve a problem in a book, I need to know whether or not the following is true:

Let f be a real-valued, decreasing differentiable function defined on the interval [1, \infty) such that \lim_{x \rightarrow \infty} f(x) = 0. Then the derivative of f is continuous.

Homework Equations



N/A

The Attempt at a Solution


Tried working directly with the definitions (decreasing function, continuity, derivative), but got nowhere. Consulted various references (such as baby Rudin and Hobson's Theory of Functions of a Real Variable), with no luck. Spent time Googling combinations of the various terms, again with no results.

I suspect that the above statement is true. The canonical example of a differentiable function whose derivative is not continuous (see here) is not monotone in any interval containing the origin. However, I can't find either a proof or a counterexample.
 
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Petek said:

Homework Statement



To solve a problem in a book, I need to know whether or not the following is true:

Let f be a real-valued, decreasing differentiable function defined on the interval [1, \infty) such that \lim_{x \rightarrow \infty} f(x) = 0. Then the derivative of f is continuous.

Homework Equations



N/A

The Attempt at a Solution


Tried working directly with the definitions (decreasing function, continuity, derivative), but got nowhere. Consulted various references (such as baby Rudin and Hobson's Theory of Functions of a Real Variable), with no luck. Spent time Googling combinations of the various terms, again with no results.

I suspect that the above statement is true. The canonical example of a differentiable function whose derivative is not continuous (see here) is not monotone in any interval containing the origin. However, I can't find either a proof or a counterexample.

Your canonical example may not be monotone near the origin, but if you change a bit you can make one that is. Suppose you subtract say, 3x?
 
Thanks for the suggestion! By subtracting 3x from the function, we subtract 3 from the derivative. That makes the derivative negative and so the original function is monotone decreasing. I'll have to think about how to apply that to my original question.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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