Continuously differentiable function

Click For Summary
SUMMARY

The discussion focuses on proving that if a function ##f## is continuously differentiable on an open interval in ##E^2## and satisfies the condition ##\partial^2f/\partial x\partial y=0##, then it can be expressed as the sum of two continuously differentiable functions ##f_1## and ##f_2## on open intervals in ##\mathbb{R}##. The proof involves integrating the mixed partial derivatives and confirming the validity of the derived expression. The participants confirm the correctness of the approach without identifying any issues.

PREREQUISITES
  • Understanding of continuously differentiable functions
  • Knowledge of partial derivatives
  • Familiarity with integration in multiple dimensions
  • Basic concepts of real analysis
NEXT STEPS
  • Study the properties of continuously differentiable functions in real analysis
  • Learn about the implications of mixed partial derivatives being equal
  • Explore the Fundamental Theorem of Calculus in multiple dimensions
  • Investigate applications of separable functions in mathematical modeling
USEFUL FOR

Students and educators in mathematics, particularly those studying real analysis and differential calculus, as well as researchers exploring properties of differentiable functions.

Lee33
Messages
156
Reaction score
0

Homework Statement



Show that if ##f## is a continuously differentiable real valued function on an open interval in ##E^2## and ##\partial^2f/\partial x\partial y=0,## then there are continuously differentiable real-valued functions ##f_1,f_2## on open intervals in ##\mathbb{R}## such that ##f(x,y)=f_1(x)+f_2(y).##

How can I prove this?

Homework Equations



None

The Attempt at a Solution



Let ##(x_0,y_0)\in E^2## and integrate twice:

##0=\int_{y_0}^y\int_{x_0}^x\partial_x(\partial_yf(x',y'))dx'dy'=\int_{y_0}^y(\partial_yf(x,y')-\partial_yf(x_0,y'))dy'=f(x,y)-f(x,y_0)-f(x_0,y)+f(x_0,y_0).##
 
Physics news on Phys.org
This looks fine. Was there any problem with this?
 
  • Like
Likes   Reactions: 1 person
Nope, I was just confirming. Thanks for confirming!
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
1K
Replies
2
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
863
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K