Contour map and Intersection points

Arcon
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Homework Statement



(i) Drawing a contour map for the function h(x.y) = -12-4x^2+16x-y^2-8y
(ii) (Continuing from i) at the point (1,-1,7) which direction to move to have
the maximum increase in height?

(iii) Find the point closest to the origin on the curve of intersection of the
plane 2y + 4z = 5 and the cone z^2= 4x^2 + 4y^2.

Homework Equations



(i) z = -12-4x^2+16x-y^2-8y (then I am stuck)

(iii) I got f = z <--(not sure if this is right),
g = 2y +4z = 5
and h = z^2= 4x^2 + 4y^2.

then gradient f = lambda * gradient g + mu * gradient h

The Attempt at a Solution



then from some caluculation i got two intersection point of (0,5/18,5/9) and (0, 1/10, 1/20) with (0, 1/10, 1/20) the point closest to the origin.
 
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Arcon said:

Homework Statement



(i) Drawing a contour map for the function h(x.y) = -12-4x^2+16x-y^2-8y
(ii) (Continuing from i) at the point (1,-1,7) which direction to move to have
the maximum increase in height?

(iii) Find the point closest to the origin on the curve of intersection of the
plane 2y + 4z = 5 and the cone z^2= 4x^2 + 4y^2.

Homework Equations



(i) z = -12-4x^2+16x-y^2-8y (then I am stuck)
Do you understand what a "contour map" IS? No, don't set h(x,y)= z. A contour map of a function of two variables is a graph is the xy-coordinates system. Set h(x,y)= equal to a number of different constants and graph each of them. (Looks to me like you will have a number of different hyperbolas with the same asymptotes.)

(iii) I got f = z <--(not sure if this is right),
g = 2y +4z = 5
and h = z^2= 4x^2 + 4y^2.

then gradient f = lambda * gradient g + mu * gradient h
Okay, that's the "Lagrange multiplier" method.

The Attempt at a Solution



then from some caluculation i got two intersection point of (0,5/18,5/9) and (0, 1/10, 1/20) with (0, 1/10, 1/20) the point closest to the origin.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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