Contradiction on kvl kcl laws question

AI Thread Summary
The discussion revolves around the behavior of a DC circuit involving capacitors and resistors, particularly focusing on the concept of "current shock" at the moment a switch is closed. When the switch is activated, a sudden voltage change occurs, causing a discontinuous jump in current through the circuit, which affects the voltage across the capacitors and resistors. This leads to a perceived contradiction in Kirchhoff's Voltage Law (KVL) due to the instantaneous changes in voltage and current. Despite this, the continuity laws still hold, as the voltage across capacitors remains continuous while the current can change abruptly. Understanding these dynamics clarifies the apparent contradictions in the application of KVL in transient states.
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http://i49.tinypic.com/1yu634.jpg

this is a part of the solution
"
the is a voltage drop on capacitor C1 which makes current shock on C1
and a current shock on R2 and R3
and it makes a KVL contradiction on the right branch and the outer branch.

and that's why the continuety laws holds"

what is current shock?
why its also on R2 and R3?
why KVL laws contradict?
why there is continuety ?
 
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Not sure what a current shock is or what contradiction they're referring to, but what they probably mean is this:

In a DC circuit, once any transients have died out, the capacitors are essentially open circuits, so no current is flowing anywhere in the circuit. If there's no current, there's no voltage drop across the resistors, so the 12-volt drop for each loop must occur across the capacitors.

At t=0, the switch is closed, causing the voltage of the point between R2 and R3 to discontinuously jump to 6 volts (relative to the bottom line of the circuit). For a capacitor, the current flowing through it may be discontinuous, but the voltage across it must be continuous. This means that t=0+, the capacitors still have a 12-volt drop across them; therefore, both resistors now have a 6-volt drop across them. The current therefore jumps discontinuously from 0 A to 1.5 A when the switch is closed.
 

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