COnversative Forces and Change in Kinetic Energy

[copitlory8]

Homework Statement

A roller coaster (365. kg) moves from A (5.00 m above the ground) to B (28.0 m above the ground). Two nonconservative forces are present: friction does -2.00 multiplied by 104 J of work on the car, and a chain mechanism does +3.00 multiplied by 104 J of work to help the car up a long climb. What is the change in the car's kinetic energy, ΔKE = KEf - KE0, from A to B?

Homework Equations

change in kinetic energy =work or final KE minus initial KE.
Work=force x distance
change in KE= .5(m)(final velocity)^2

The Attempt at a Solution

I used the constant acceleraton euqation to solve for final velocoty. And the formula .5(m)(final velocity)^2 to calculate KE.
I got 10000. This answer was wrong.

 

[merryjman]

You are missing another type of work here: the work done against the coaster by Earth's gravity. Plus, there's never any need to use acceleration or velocity in this question; it is purely Work/Energy.

 

[copitlory8]

so how would i incorporate Earth's gravity 9.8?

 

[merryjman]

9.8 is acceleration, not work. As you wrote, work is force multipled by distance.

 

[sezw]

_Ep=_Ek E_p=mgh (mass*gravity*height) _Ek=1/2mV² V is velocity at that point you do not need to find final velocity you must manipulate the equations mgh=1/2*mv² = [STRIKE]m[/STRIKE]gh=1/2* [STRIKE]m[/STRIKE] v² m cancels out you just need to manipulate the equation and you can find anything

 

[copitlory8]

okay but what do i do about the two nonconservative forces given that -2x10^3 is work done by earth

 

[sezw]

F_f as i know it is equal to F_n * \mu \mu= to the kinetic force of friction. NOTE: there are 2 types of friction static and kinetic static is just simply what the friction force is when the object is at rest kinetic friction is what most people find because it is what is most commonly used and referred too (or so i have been told) i don't think this answer your question but i think it should help cause i was think along the lines of wtf? what does energy have to do with this but looking at it again i realize that one could manipulate the equation so that it may be a vector with velocity if i might ask what level of physics is this?

 

[merryjman]

You've already got all you need, forget about the force of friction. You've got +30,000 J of work done by the chain, -20,000 J of work done by friction, and you've got to figure out the work done by gravity (-2,000 J is not correct for that). Then just figure out how much all this work adds up to, and you're done!

 

[copitlory8]

that is the problem. i don't understand work by gravity!

 

[copitlory8]

this is high level college physics

 

[merryjman]

what is the force of gravity on the coaster, and does it point up or down? how far does the rollercoaster move while under the influence of this force, and does it move up or down? Work is force times distance, and is either positive or negative depending on the directions of force and distance, and there you go.

 

[sezw]

lol I'm about to write my grade 11 level final exam for physics in about 14 hrs and this stuff almost makes total sense

 

[copitlory8]

it points down.
distance is 23

 

[copitlory8]

so after i find the fwork what do i do?

 

[copitlory8]

i still don't get this