Convert equation from cartesian to spherical

glog
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This should be relitively simple:

y = x ... convert to spherical coords:

p*sin(r)*sin(t) = p*sin(r)*cos(t)

which reduces to...

sin(t) = cos(t)

tan(t) = 1 (is this right?)
t =~ 0.78... (Can i get a nice fraction for this?)

Any help is appreciated.

- glog
 
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Looks good to me.

pi/4

you simply substitute and simplify.
 
in other words, "y= x" in spherical coordinates reduces to the set of points where t= \theta= \pi/4, r= \phi and p= \rho can be anything. Do you see that that is, in fact, the same as the plane y= x?
 
yep makes perfect sense...
only one angle is fixed :)
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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