Converting Cartesian to Cylindrical Coordinates

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Homework Help Overview

The discussion revolves around converting Cartesian coordinates to cylindrical coordinates, specifically focusing on the transformation of given equations at specified points. The original poster presents two equations, A and B, and seeks clarification on how to perform the conversion correctly, particularly regarding the bolded aspects of the problem.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the confusion surrounding the conversion process and the interpretation of unit vectors in cylindrical coordinates. Some participants suggest that the original poster may have misunderstood the problem's requirements.

Discussion Status

The conversation is ongoing, with participants providing insights into the nature of unit vectors in cylindrical coordinates and emphasizing the importance of understanding their orientation at different points. There is no explicit consensus on how to proceed with the original poster's request for an example.

Contextual Notes

Participants note that the original poster's attempts at conversion may not align with the problem's intent, which involves expressing vectors in terms of unit vectors rather than simply converting coordinates. There is also a mention of a reference link that some participants found unhelpful.

Shaheers
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Homework Statement



Hi i have a question that how to convert the co-ordinates according to following statement?
Its no difficult to solve the simple conversion but the bold one are confusing me.


A=4x-2y-4z
Transform it into cylindrical co-ordinate system at P (ρ=4, ϕ=120o ,z=2)

B=15x+10y
Transform it into cylindrical co-ordinate system at P(x=3, y=4, z=-1)





2. The attempt at a solution

Equations for converting Cartesian to cylindrical coordinates:

r= [x2 + y21/2
ϕ= tan-1= y/x
z=z

by putting values
For First question:
r=√20=4.472
ϕ= -26.57
z=-4

For Second question:
r= 18.03
ϕ= 33.69
z=0
 
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This is common point of confusion. What you've done is convert the Cartesian coordinates (4, -2, -4) to the equivalent cylindrical coordinates. What the problem is asking you to do, however, is different.

Take a look at the diagram at the start of this page:

http://mathworld.wolfram.com/CylindricalCoordinates.html

At each point, there are associated unit vectors ##\hat{\rho}##, ##\hat{\phi}##, and ##\hat{z}##. Their directions depend on which point you're at. For example, if you're at the point (1, 0, 0), ##\hat{\rho}## would point along the +x-direction, and ##\hat{\phi}## would point in the +y direction. If you're at the point (0, 1, 0), ##\hat{\rho}## would point in the +y direction, and ##\hat{\phi}## would point in the -x direction.

Given the information in bold, you can figure out what ##\hat{\rho}## and ##\hat{\phi}## are. ##\hat{z}## always points in the +z direction. Once you know what the unit vectors are equal to, you're supposed to express the vectors A and B in terms of them.
 
unfortunately i can't understand from that given link, kindly give an example by solving one of the equation or any of. . .
 
Sorry, we don't do your homework for you here. If you can't see what I tried to explain from the diagram, I suggest you consult your textbook for a more detailed explanation.
 
I doesn't mean that, i just want to say that, if you please tell this by example by taking any random point P, if such an example is given on textbook, i don't need to refer from internet
 
My point was that I would have liked to see even a minimal attempt from you to try understand what's going on instead of simply saying "I don't get it."

At each point, there are associated unit vectors ##\hat{\rho}##, ##\hat{\phi}##, and ##\hat{z}##. Their directions depend on which point you're at. For example, if you're at the point (1, 0, 0), ##\hat{\rho}## would point along the +x-direction, and ##\hat{\phi}## would point in the +y direction. If you're at the point (0, 1, 0), ##\hat{\rho}## would point in the +y direction, and ##\hat{\phi}## would point in the -x direction.
Say you have a vector field ##\vec{V}(\vec{r})##, and at both ##\vec{r}=(1, 0, 0)## and ##\vec{r}=(0, 1, 0)##, it points in the +x direction.

At the point (1, 0, 0), you'd say ##\vec{V}(1, 0, 0) = \hat{\rho}##. At the point (0, 1, 0), however, the basis vectors point in different directions. In this case, you'd have ##\vec{V}(0, 1, 0) = -\hat{\phi}##.
 

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