Convex mirror question how long the image is?

AI Thread Summary
The discussion revolves around calculating the image distance and size of a robin using a convex mirror. The mirror's focal length is determined to be 10 cm, and the object distance is 150 cm. The image distance is calculated as -9.4 cm, indicating a virtual image. The magnification is found to be 0.06, leading to an image size of 0.75 cm when multiplied by the robin's height of 12 cm. Clarifications were made regarding a typo in the calculations, confirming that the object distance should indeed be 150 cm.
batcave1985
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Shiny lawn spheres placed on pedestals are convex mirrors.
One such sphere has a diameter of 40 cm. A
12 cm long robin sits in a tree 1.5 m from the sphere.
(a) Where is the image of the robin?
(b) How long is the image?
f=R/2 to find radius
1/v=1/f-1/u to find image distance (the mirror equation)
M=v/u magnification and length (maginification equation)
my answer just not to sure if its right.
a)
f=r/2
=20/2
f=10cm
u=150cm

1/v=-1/1-1/50
v= -9.4cm

b) m=v/u
= -9.4/150
= 0.06cm

not to sure if that was the way to go.
 
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batcave1985 said:
Shiny lawn spheres placed on pedestals are convex mirrors.
One such sphere has a diameter of 40 cm. A
12 cm long robin sits in a tree 1.5 m from the sphere.
(a) Where is the image of the robin?
(b) How long is the image?



f=R/2 to find radius
1/v=1/f-1/u to find image distance (the mirror equation)
M=v/u magnification and length (maginification equation)



my answer just not to sure if its right.
a)
f=r/2
=20/2
f=10cm
u=150cm

1/v=-1/1-1/50?
v= -9.4cm

b) m=v/u
= -9.4/150
= 0.06cm

not to sure if that was the way to go.

I do not understand the line with ?

For question b, you gave the magnification, (with wrong sign) instead of the size.

ehild
 
ehild said:
I do not understand the line with ?

For question b, you gave the magnification, (with wrong sign) instead of the size.

ehild

its suppose to be
1/v=1/f-1/u (trying to find image distance)
1/v=1/-10 -1/50
v= -9.4cm

then with part b i think i use the magnification and multiply it with the height of object to get image size

0.06 x 12cm= 0.75cm
 
batcave1985 said:
its suppose to be
1/v=1/f-1/u (trying to find image distance)
1/v=1/-10 -1/50
v= -9.4cm
Where does 50 come from? The object distance is 150 cm.

batcave1985 said:
then with part b i think i use the magnification and multiply it with the height of object to get image size

0.06 x 12cm= 0.75cm

that is correct.
 
ehild said:
Where does 50 come from? The object distance is 150 cm.



that is correct.

Yes sorry another typo it is 150 i did the calculation with 150 but typed in 50.
 
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