A piece of copper wire has a resistance per unit length of 6.40e-3 ohm/m. The wire is wound into a thin, flat coil of many turns that has a radius of 0.190 m. The ends of the wire are connected to a 12.0 V battery. Find the magnetic field strength at the center of the coil.(adsbygoogle = window.adsbygoogle || []).push({});

R/L = 6.40e-3 ohm/m

r = 0.190 m

V = 12.0 V

u0 = 4pi e -7 Tm/A

B = ? T

Equations:

V = IR (I = V/R)

B = u0 * n * I

so B = u0 * n * (V/R)

I don't know where to go from here.

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# Homework Help: Copper wire magnetic field

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