Correspondence Theorem for Normal Subgroups in Groups of Order 168

tyrannosaurus
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Homework Statement



Show that if G is a group of order 168 that has a normal subgroup of order 4, then G has a normal subgroup of order 28.


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The Attempt at a Solution


Let H be a normal subgroup of order 4. Then |G/H|=42=2*3*7, so then G?N has a unique, and therefore normal Sylow 7-subgroup, let's call it K.
I was told to use the correspondence theorem, but I am not sure where it works in here. any ideas?
 
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Why don't you start by stating what the correspondence theorem says? The result you are seeking is an immediate consequence.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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