Cost of Rest Energy of 1.0 Kg at $0.60/kWh

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The discussion focuses on calculating the cost of the rest energy of a 1.0 kg mass using the equation E=mc^2, resulting in 9E16 Joules. To convert this energy into kilowatt-hours (kWh), the conversion factor of 1 kWh equaling 3.6E6 Joules is applied. The total cost is then determined by multiplying the energy in kWh by the utility rate of $0.60 per kWh. The final calculation shows that the cost amounts to approximately 15 billion dollars. This highlights the significant expense associated with the energy equivalent of mass at rest.
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Homework Statement



How much would the rest energy of a 1.0 Kg mass cost at the typical utility rate of $0.60/ kWh?

Homework Equations



E=mc^2

The Attempt at a Solution



Heres what somone told me from another website:

"The rest energy of a mass is the energy calculated by E=mc^2 when the mass is at rest.

E = (3E8 m/s)^2 * 1kg = 9E16 J

1 kWh = (1000 J/s)(3600 s) = 3.6E6 J

Energy * Cost/Energy = Cost
(9E16 J) * (1 kWh / 3.6E6 J) * ($0.60 kWh) = 15 billion dollars"

but i don't understand the last part, where they multiply (9E16 J) * (1 kWh / 3.6E6 J) * ($0.60 kWh). The eprson said Energy * Cost/Energy = Cost, so wouldn't that just be (9E16 J)(($0.60 kWh)/(9E16 J))?
 
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Hi jackster18,

The first two terms

<br /> (9\times 10^{16} \mbox{ J}) \times \left(\frac{1 \mbox{ kWh} }{ 3.6\times 10^6 \mbox{ J}}\right)<br />

converts the energy in units of Joules to units of kWh.

Once you have the amount of energy in kWh, you know that each kWh costs 60 cents. So you multiply:

<br /> (\mbox{energy in kWh}) \times \left(\frac{\$ 0.60 }{ \mbox{kWh}}\right)<br />

to find the total cost in dollars.
 
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