Coulomb's Law and Final Angle of Dust Cobweb

[leafsfan2]

(I posted this in the wrong section earlier, hopefully i got it right this time...)
1.Homework Statement

A dust cobweb is drawn from an initial vertical position toward a nearby wall by an electrostatic force. Assume the cobweb to be like a single dust ball of mass 2.0 x 10^-7g suspended on a massless string of length 0.42 m connected a horizontal distance of 0.35 m from the wall, as shown below. The tethered dust ball is drawn to the wall by another similar dust ball of opposite charge, -q = -3.0 x 10-6C.
a)what final angle does the cobweb make to the vertical?


2. Homework Equations
Fe = (kq1q2)/d^2



where Fe is the electric force between two objects
K is Coulomb's constant (9.0 x 109 Nm2/C2)
q1 is object 1's electric charge
q2 is object 2's electric charge
d is the distance between centers of charged objects

I tried using components, so:
Ft=Fe/sinθ
And
Fg=Ftcosθ
So I substituted but I end up with two variables (d and θ) so I'm not sure what to do.

(Sorry for any typos and the horrible formatting, I'm posting this off a phone)

 

[ehild]

Could you show a picture showing the dust balls and the forces to make the problem more clear, please?

ehild