Coulomb's Law: Simple Harmonic Motion of a Charge Between Two Fixed Charges

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The discussion revolves around the behavior of a negatively charged particle in the electric field created by two fixed positively charged particles. When the third particle is placed close to the midpoint between the two charges, its motion can be approximated as simple harmonic motion if the distance x is small compared to d. The period of this motion can be determined using the relevant physical constants and formulas. Additionally, the speed of the negatively charged particle at the midpoint can be calculated based on its initial position and the forces acting on it. Understanding these principles is essential for solving the problem effectively.
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Two identical particles, each having charge +q, are fixed in space and separated by a distance d. A third particle with charge −Q is free to move and lies initially at rest on the perpendicular bisector of the two fixed charges a distance x from the midpoint between those charges (see figure below).

(a) Show that if x is small compared with d, the motion of −Q is simple harmonic along the perpendicular bisector. (Do this on paper. Your instructor may ask you to turn in this work.)

There is more to this problem but the first question I don't even know what is asking.

 
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Also, just looked at the second two questions, don't know where to start...
(b) Determine the period of that motion. (Use the following as necessary: π, q, Q, m for the mass of charge Q, d, and ke.)
T =

(c) How fast will the charge −Q be moving when it is at the midpoint between the two fixed charges if initially it is released at a distance a << d from the midpoint? (Use the following as necessary: π, q, Q, m for the mass of charge Q, d, and ke.)
 
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