Couple calculations Polar to Rectangular Form

AI Thread Summary
The discussion focuses on calculating the sum of two complex currents, i1 and i2, converting them from polar to rectangular form. The values for i1 and i2 are provided, with i1 calculated as -0.0142 - j0.0909. The resulting sum, i1 + i2, is computed as 0.0426 - j0.1273. The final conversion of this sum to polar form yields i1 + i2 = 0.1342 < -71.4976. The calculations presented are confirmed to be correct.
shaltera
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Homework Statement



I need to find i1+i2

Homework Equations



for i1=0.092<-98.86
i2=-4i1-j10/25=-4i1-0.4

i1=0.092<-98.86
x=rcosθ=0.092cos(-98.86)=-0.0142
y=rsinθ=0.092sin(-98.86)=-0.0909
i1=-0.0142-j0.0909

Therefor
i2=-4(-0.0142-j0.0909)-j0.4=0.568+j3636-j0.4=0.568-j0.0364i1+i2=-0.0142-j0.0909+0.568-j0.0364=0.0426-0.j1273

Covert 0.0426-0.j1273 to polar form i1+i2=0.1342<-71.4976

Correct?

The Attempt at a Solution

 
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Your calculations look fine.
 
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