No I don't mean like a voltage divider. I mean the circuit arrangement is a voltage divider.
Perhaps the attached sketch will help.
Since you have no particular circuit in mind I've kept it general.
The first sketch shows two single ended stages or amplifiers A1 & A2, the first feeding the second via coupling capacitor C1 the second feeding a load via coupling capacitor C2.
It is worth noting that we use (need) coupling capacitors because the DC levels at the stages may not be (probably are not) the same so we block DC whilst allowing the AC signal through.
The second sketch shows how the signal from a stage is applied.
The stage output impedance is inseries with the coupling capacitor and the input impedance of the next stage.
It is normal to make Zload>> Zout and in general we choose circuit values so this is the case and we then ignore Zout.
We want the bulk of the signal to appear across Zin or Zload, not across Zcapacitor so we choose the capacitor so that
Zload>> Zcapacitor
To put some real values into the example, say the first stage is a preamp with an output impedance of 600 Ohms and the second stage is a power amp with an input impedance of 10K.
We seek a capacitor impedance that will be less than 1/10 the input impedance of the power amp ie 1k.
Say our lowest frequency of interest is 100 Hz then
[tex]{C_1} = \frac{1}{{2\pi f{X_c}}} = \frac{1}{{2\pi {{10}^2}{{10}^3}}} = \frac{{10*{{10}^{ - 6}}}}{{2\pi }}microfarads \approx 1.5\mu F[/tex]
For the power amp feeding an 10 ohm loudspeaker the output impedance is usually less than 0.1 ohm and again may be neglected.
A 100 Hz calculation for C2 shows
[tex]{C_2} = \frac{1}{{2\pi f{X_c}}} = \frac{1}{{2\pi {{10}^2}1}} = \frac{{{{10}^4}*{{10}^{ - 6}}}}{{2\pi }}microfarads \approx 1500\mu F[/tex]
So you can see why we have large speaker coupling capacitors and small inter amplifier caps.
go well