Covariant derivative of the Riemann tensor evaluated in Riemann normal

  • #1
minits
13
0
TL;DR Summary
Covariant derivative of the Riemann tensor evaluated in Riemann normal coordinates
Hello everyone,

in equation 3.86 of this online version of Carroll´s lecture notes on general relativity (https://ned.ipac.caltech.edu/level5/March01/Carroll3/Carroll3.html) the covariant derviative of the Riemann tensor is simply given by the partial derivative, the terms carrying the Christoffel symbols seem to vanish. I assume this results from the note that it is evaluated in Riemann normal coordinates. I know one can choose the coordinate system so that a given Christoffel-symbol vanishes but in this case there are so many to handle so that I am not convinced this is working. Can someone please give me an input on how to make myself clear that it works? Thanks in advance!
 

Answers and Replies

  • #2
martinbn
Science Advisor
3,106
1,464
Can you be more specific. What doesn't seem to work? It looks perfectly fine.
 
  • #3
Gaussian97
Homework Helper
683
406
Summary:: Covariant derivative of the Riemann tensor evaluated in Riemann normal coordinates

Hello everyone,

in equation 3.86 of this online version of Carroll´s lecture notes on general relativity (https://ned.ipac.caltech.edu/level5/March01/Carroll3/Carroll3.html) the covariant derviative of the Riemann tensor is simply given by the partial derivative, the terms carrying the Christoffel symbols seem to vanish. I assume this results from the note that it is evaluated in Riemann normal coordinates. I know one can choose the coordinate system so that a given Christoffel-symbol vanishes but in this case there are so many to handle so that I am not convinced this is working. Can someone please give me an input on how to make myself clear that it works? Thanks in advance!
Riemann normal coordinates are, by definition, coordinates in which at a specific point ##x_0## the metric is minkowskian and (all) the Christoffel symbols vanish.
Therefore covariant derivatives evaluated at this point ##x_0## are just ordinary derivatives.
 
  • #4
minits
13
0
Thanks for your answer! I thought in this case the Riemann tensor should vanish as well due to it´s definition in form of products and derivatives of Christoffel symbols but one will probably simply use the argument that tensors are independent of any basis.
 
  • #5
41,289
18,918
I thought in this case the Riemann tensor should vanish as well due to it´s definition in form of products and derivatives of Christoffel symbols
The Christoffel symbols vanish at the origin of Riemann normal coordinates, but their derivatives do not vanish at that point. So the Riemann tensor, since it includes derivatives of the Christoffel symbols, does not vanish at that point.
 
  • Like
Likes JD_PM and Orodruin
  • #6
minits
13
0
Ah ok thanks for your answer!
 

Suggested for: Covariant derivative of the Riemann tensor evaluated in Riemann normal

Replies
24
Views
976
Replies
11
Views
697
Replies
2
Views
423
  • Last Post
Replies
5
Views
742
Replies
3
Views
781
  • Last Post
Replies
5
Views
546
Replies
21
Views
779
Replies
1
Views
493
  • Last Post
Replies
2
Views
421
Replies
1
Views
563
Top