Crash Acceleration: Calculate SUV's Rate of Change in Velocity

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To calculate the acceleration of the SUV during the crash, the relevant kinematic equation is Vf^2 = Vi^2 + 2ad, where Vf is the final velocity (0 m/s), Vi is the initial velocity (12.5 m/s), and d is the distance (1.2 m). Rearranging the formula to solve for acceleration (a) allows for the calculation of the SUV's rate of change in velocity. By substituting the known values into the equation, the acceleration can be determined. It is crucial to consider the direction of the acceleration, which will be negative since the vehicle is decelerating. The final calculation will yield the SUV's acceleration during the crash.
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Homework Statement


A person drives his SUV into a concrete wall. The car was initially moving East at 12.5m/s and the hood crumples a distance of 1.2m during the crash. What is the acceleration of the car during the crash? (don't forget directions when dealing with acceleration)

I don't even know where to begin.
 
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What constant acceleration formulae do you know?
 
almost all of them, i was given a big formula sheet that we are allowed to use in the test.
 
So this is what we have:

initial velocity (12.5ms-1)
final velocity (0.0ms-1)
distance (1.2m)

What we need:

acceleration

What formula do you know that uses only these variables?
 
Vf^2 = Vi^2 +2ad
 
Perfect! Now we just need to re-arrange that formula and solve for a!
 

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