Critical points of differential equation

samee
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Homework Statement



Determine the location and type of all critical points of the given equations and sketch the phase portrait

y"+cosy=0



The Attempt at a Solution



I've done some like this before but they were all systems of equations. I'm actually not sure how to do the simpler version >_< I think this is asking for maxima and minima? is that right?
 
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It's NOT simpler. This is only one equation but is second order. What you want is two first order equations. Define x by x= y'. Then y''= x' so y''+ y= 0 becomes x'+ y= 0 or x'= -y.

You now have the two equations x'= -y and y'= x.
 
Okay, so for my problem I have
x=y'
x'=y"
so I substitute and
x'+cosy=0
x'=-cosy

so my system of equations is;

y'=x
x'=-cosy

right? Then I just solve like it's a system of equations and look for the singularities as the critical points?
 
Ah! No wait, there's more! I know what I'm doing now, silly me. I set x' and y' to zero and solve for the points.

x'=0, ∴x=0
y'=0, -cosy=0, ∴y=(1/2)(2n+1)pi

So I have infinite points along the y-axis. I used

http://www.math.rutgers.edu/courses/ODE/sherod/phase-local.html

to graph the phase portrait and found that every other critical point is a saddle point, then a center point.

SO! how do I say that one is a saddle, then the next is a center?
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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