Cross product and the angles of a prallelogram

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Cross product and the angles of a prallelogram's diameters

Homework Statement



With the help of cross product prove: if the angle between the diameters of a parallelogram is 90 degrees, then the parallelogram is a rectangular.

Homework Equations



A\timesB=(surface of the parallelogram)


The Attempt at a Solution

 
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What is |\mathbf{A} \times \mathbf{B}|? How does it depend on the angle between the two vectors?
 
A and B are not the diameters, they are the sides. As I mensioned |\mathbf{A} \times \mathbf{B}|= (the surface of the parallelogram)
 
what are the diameters? the diagonals? if so you should be able to write them as a vector sum of the sides...
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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