Cross product in cylindrical coordinates

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fishingspree2
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In my physics textbook we have
[itex]d\vec{l}=\hat{z}dz[/itex]
and then it says
[itex]d\vec{l}\times \hat{R}=\hat{\phi}\sin \left (\theta \right )dz[/itex]

How so? What is [itex]\hat{z}\times\hat{R}[/itex]? If it is [itex]\hat{\phi}[/itex] then where does the sine come from?
 
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SteamKing said:
Check the definition of cross product.
If i use the fact that a X b = |a| |b| sin(theta) then I understand where the sine comes from, it this case it would also mean that z X R is in the φ direction if [itex]d\vec{l}\times \hat{R}=\hat{\phi}\sin \left (\theta \right )dz[/itex] is correct.

but when I compute z X R using the 3x3 matrix
R φ z
0 0 1
1 0 0

I get +φ, and there is no sine.
 
Any idea what am I missing?
 
It looks like [itex]\hat{z}[/itex] is a unit vector in the axial direction, [itex]\hat{\phi}[/itex] is a unit vector in the circumferential direction, [itex]\hat{R}[/itex] is a unit vector pointing from the origin in an arbitrary spatial direction, and [itex]\theta[/itex] is the angle between the unit vector [itex]\hat{R}[/itex] and the z axis.

[tex]\hat{R}=\sin(\theta)\hat{r}+\cos(\theta)\hat{z}[/tex]

where [itex]\hat{r}[/itex] is a unit vector in the radial coordinate direction.