Current and resistance of wire heating up water

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The discussion revolves around calculating the average power required to heat 250 g of water from 20°C to 100°C using a Nichrome immersion heater connected to a 120V power supply. Participants express concerns about the assumptions in the problem, particularly regarding the heater's constant temperature and its thermal mass. The calculations involve determining resistance at different temperatures and deriving relationships between wire diameter, resistivity, and resistance. There is a consensus that the question may be poorly designed, as it overlooks practical heating dynamics. Overall, the thread highlights the complexities of thermal calculations in electrical heating scenarios.
Shelby8
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Homework Statement


An office worker uses an immersion heater to warm 250 g of water in a light, covered, insulated cup from 20 degrees C to 100 degrees C in 4 minutes. The heater is Nichrome resistance wire connected to 120V power supply. Assume wire is at 100 degree C during 4 minute time interval.

a) calculate average power required to warm the water to 100 degree C in 4 min
b) calculate the required resistance in the heating element at 100 degree C
c) calculate the resistance of the heating element at 20 degree C
d) derive a relationship between the diameter of the wire, resistivity at 20 degree C, rou (po), the resistance at 20 degree C, Ro, and the length L
e) If L = 3 m, what is the diameter of the wire?

What we are given:
mass of water = 250 g
density of water = 1000 kg / m^3
change in T = 80
V = 120V
t = 4 minutes
p of Nichrome = 150 *10^-8
coeff of resistivity of Nichrome = 0.4 * 10^-3

Homework Equations


P = I*V = V^2/I = I^2*R
R = V/I
R = Ro [1 + coefficient of resistivity (T - To)]
R = p L / A
I = Q / t

The Attempt at a Solution


a) calculate average power required to warm the water to 100 degree C in 4 min
density = m / v ... v = m / density
v = A * L
v = 250 / 1000 = .25 m ^3 = A * L
R = p L / (.25/L) = p L^2 / .25

How do I calculate I for Power without knowing the charge?
 
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Shelby8 said:
How do I calculate I for Power without knowing the charge?
You should know (or be able to look up) an expression that relates power to voltage and current. Of course, you'll need to have completed part (a) to find the power requirement first.
 
If the wire is at 100C then it can't heat the water in 4 minutes or any other finite amount of time ...
 
+1

I suspect a badly designed question. I think they said to assume the wire is at a constant temperature so you would ignore it's thermal mass.
 
CWatters said:
+1

I suspect a badly designed question. I think they said to assume the wire is at a constant temperature so you would ignore it's thermal mass.
Either that or the office worker wanted a long rest pause ... :smile:
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

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