Current and Voltage in a transformer

AI Thread Summary
In a transformer with a primary power of 100W, a changing flux of 25 Wb/s, 100 primary loops, and 500 secondary loops, the primary voltage is calculated to be 2500V. Using the power formula P=V1I1, the primary current is determined to be 1/25 A. The secondary voltage is found to be 12500V based on the turns ratio, and the secondary current is calculated as 1/125 A. The calculations confirm the relationships between voltage, current, and power in a perfect transformer. Overall, the discussion successfully resolves the problem with accurate values for both primary and secondary parameters.
btpolk
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Homework Statement



The primary coil in a transformer has a power of 100W. The flux through a single loop in the primary is changing at a rate of 25 Wb/s. The primary has 100 loops and the secondary has 500 loops. Assuming a perfect transformer (no losses), determine the current and voltage in both the primary and secondary.


Homework Equations



V1/V2=N1/N2=I2/I1

?


The Attempt at a Solution



V1/V2=1/5→5V1=V2

I1/I2=5→5I2=I1

I have no knowledge of an equation/relationship between Wb/s and the other variables in this problems nor can I find one. Please Help.
 
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A hint can be found in the units: A Weber (Wb) has the equivalent units of V*s (that is, one Weber is a Volt-second).

Given the rate of change 25 Wb/s for a single loop, what's the voltage on the primary?
 
So it would be 25W then?
 
i mean 2500W since its per loop
 
Sorry, I don't understand your response. Your given information states that there is 100W associated with the primary. What's this 2500W you're proposing? Or do you mean 2500V? That would be a reasonable value :smile:

So, if the voltage on the primary is 2500V, what's the current?
 
Sorry, I did mean 2500V.

So to find the current I would use

P=V1I1

which would mean that the current would have to equal 1/25 A
 
btpolk said:
Sorry, I did mean 2500V.

So to find the current I would use

P=V1I1

which would mean that the current would have to equal 1/25 A

Yes. Now, how will you find the secondary voltage and current?
 
5V1=V2

V2=12500V

P=I2V2

I2=1/125 A

Is that right?
 
btpolk said:
5V1=V2

V2=12500V

P=I2V2

I2=1/125 A

Is that right?

Your results look good.
 
  • #10
Thanks for the help! I really appreciate it
 
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