Current Electricity - current flowing through hand

Click For Summary

Homework Help Overview

The discussion revolves around a problem in current electricity, specifically focusing on calculating the resistance of human skin and estimating the current flowing through a person who accidentally contacts a live wire. The problem involves resistivity values and geometric considerations of contact area.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of resistance based on skin thickness and area, with one participant successfully solving the first part of the problem. Questions arise regarding the effect of contact area on resistance and the implications of potential difference along the wire.

Discussion Status

Some participants have provided guidance on the relationship between contact area and resistance, while others are exploring the implications of potential difference along the wire. There is an ongoing exchange of ideas, with no explicit consensus reached yet.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information available for discussion. The original poster expresses difficulty in solving the second part of the problem, indicating a need for further clarification on the concepts involved.

sharkey1314
Messages
17
Reaction score
0
Current Electricity -- current flowing through hand

Homework Statement



i)For a layer dry skin 1mm thick, determine the resistance of a 1 cm^2 area of skin.
Resistivity of dry skin : 3 x 10^4 ohms m

[3.0 x 10^5 ohms ]
ii)A person, who is well-earthed, accidentally grabs a wire of diameter 0.4 cm at a potential of 50V. His hand makes contact with the whole circumference of the wire over a distance of 9cm.
The average thickness of skin of his hand is 1mm. Estimate the current flowing through him.

[1.89 mA ]

Homework Equations



Resistance = resistivity(length)/area
V = IR

The Attempt at a Solution



For i) , I managed to solve it.
Using the equation directly.

For ii), I couldn't get the answer.

First, I calculate the surface area of the cylinder ( wire ) where it is in contact with the wire.

Surface area = pi . diameter . length
= pi . (0.4 x 10^-2) . (9 x 10^-2)
= 0.0011309 m^2
Then I multiply this surface area with the resistance of dry hand obtain in i)

Total resistance = surface area x resistance of dry skin 1 mm thick, area of 1m^2
= 0.0011309 x 3.0 x 10^5

Next, I used V = IR. Sub in total resistance and P.D of 50 V
The answer I got was 0.147 A. Totally off.

Thanks for the time !
 
Physics news on Phys.org
hi sharkey1314! :smile:
sharkey1314 said:
Then I multiply this surface area with the resistance of dry hand obtain in i)

but won't the resistance go down if the area of contact increases? :wink:
 


Thanks a lot. I re-used the equation for resistance to find the new resistance of the hand. Then, after using V = IR, I managed to get the answer =D

Just to clarify, what does a potential of 50V means ? And does the potential changes along the length of the wire. i.e. the start and end point will have different potential ? If so, does the answer change since potential varies.
 
sharkey1314 said:
Just to clarify, what does a potential of 50V means ?

it means the potential difference between the wire and the ground …

ie from your hand to your foot! :biggrin:
And does the potential changes along the length of the wire. i.e. the start and end point will have different potential ? If so, does the answer change since potential varies.

Yes, but only very slightly …

the drop in potential along a wire is IR, and R for a wire is usually very small! :smile:
 

Similar threads

  • · Replies 42 ·
2
Replies
42
Views
6K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
2
Views
1K
Replies
7
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
1
Views
2K
Replies
4
Views
2K