Current Through A Resistor That Is In Parallel With A Capacitor

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Homework Help Overview

The discussion revolves around a problem involving a resistor in parallel with a capacitor, specifically focusing on the time constant and current through the resistor as the capacitor charges. The subject area includes circuit analysis and the application of Kirchhoff's Voltage Law.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to determine the appropriate resistance value for calculating the time constant in the context of a capacitor charging through a resistor. They express uncertainty about the role of the parallel resistor and mention Thevenin's Equivalence as a potential method but find it confusing.

Discussion Status

Some participants suggest using Thevenin's method as a viable approach, while others acknowledge the original poster's concerns about its relevance to their curriculum. There is an ongoing exploration of how to apply Kirchhoff's laws and the implications of the time constant in this scenario.

Contextual Notes

The original poster notes that Thevenin's method is not part of their first-year physics curriculum, which raises questions about the appropriateness of using it for their assignment. There is a mention of potential credit implications for using methods outside their taught material.

solour
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Homework Statement


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My question is regarding part C of the question.

Homework Equations


V = IR
V(t) = V(1-e^(-t/tau))

The Attempt at a Solution


My idea is to use Kirchoff's Voltage Law and find the voltage of the capacitor as a function of time, then since the voltage across capacitor is the same as voltage across resistor I can simply divide that by a constant R and obtain current as a function of time.

The problem I am running into is: I am unsure what to put as R in the time constant.
To my understanding time constant is the amount of time it takes to charge the capacitor to about 60%, and from my instinct it does not depend on the resistance of light bulb that is in parallel with the capacitor. Therefore Tau(time constant) = 50*Capacitance.

However, I am unsure of what I said above, and would like to know if there's a more definitive way to find the R value for time constant. I did see one approach which uses Thevenin's Equivalence but it was very confusing.
 
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Thevenin is the way.

Show what you've tried and where it gets confusing.
 
solour said:

Homework Statement


http://imgur.com/a/KnYI2
http://imgur.com/a/KnYI2
My question is regarding part C of the question.

Homework Equations


V = IR
V(t) = V(1-e^(-t/tau)

The Attempt at a Solution


My idea is to use Kirchoff's Voltage Law and find the voltage of the capacitor as a function of time, then since the voltage across capacitor is the same as voltage across resistor I can simply divide that by a constant R and obtain current as a function of time.

The problem I am running into is: I am unsure what to put as R in the time constant.
To my understanding time constant is the amount of time it takes to charge the capacitor to about 60%, and from my instinct it does not depend on the resistance of light bulb that is in parallel with the capacitor. Therefore Tau(time constant) = 50*Capacitance.
gneill said:
Thevenin is the way.

Show what you've tried and where it gets confusing.
I am taking first year physics and Thevenin is not in the curriculum so I'm not sure how to calculate it. I will learn how it works then!
 
solour said:
I am taking first year physics and Thevenin is not in the curriculum so I'm not sure how to calculate it. I will learn how it works then!
Okay. After you've done some research come back with any questions.
 
solour said:
I am taking first year physics and Thevenin is not in the curriculum so I'm not sure how to calculate it. I will learn how it works then!
Thevenin would be the easiest and most practical way of doing this problem. But if it is not in your curriculum, I am not sure if you'll get full credit for this question if it is a part of your assignment or exam. After solving this problem using Thevenin, you might want to try the usual mesh analysis KVL method.

But the Thevenin method will surely be very useful for you to analyse circuits with increased complexity.
 

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