Calculating Current Through a Capacitor with a Constant Voltage Input

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To calculate the current through a capacitor with a constant voltage of -20V, the relevant formula is i = C dv/dt, where dv/dt represents the rate of change of voltage over time. Since the voltage is constant, dv/dt equals zero, resulting in a current of zero through the capacitor. Without a change in voltage, it is impossible to derive a current value. The discussion emphasizes that additional information or a varying voltage is necessary to calculate current effectively. Therefore, with constant voltage, the current through the capacitor remains zero.
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calculate the current through the capacitor 100mF in response of voltase 20-
 
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Your thoughts?
 
I want to find out the i if v across capacitor is -20v

I know the formula is i = C dv/ dt

but here I have no t

only capacitance and voltage
 
Last edited:
circuitaki said:
I want to find out the i if v across capacitor is -20v

I know the formula is i = C dv/ dt

but here I have no t

only capacitance and voltage
It's not a t. It's a derivative with respect to time. dv/dt is the rate of change of voltage with respect to time. Can you find that?
 
hi dear,

if t is the rate of change of time then how can i drive it kindly guide
 
With the given information, you can only get the charge on the capacitor. Calculating i is impossible without more information.

I suggest you look carefully at the problem statement again, is there any other information? Or a figure?
 
hi dear,


Kindly check that we have voltage and capacittance as

v= -20 v

and

capacitace


5 mF
 
Maybe this question is easier than we are making it out to be.

If v = a constant -20V, then

dv/dt = ____?​
 
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