How Do Dependent Sources Affect Voltage and Power Calculations in Circuits?

AI Thread Summary
Dependent sources significantly influence voltage and power calculations in circuits, as evidenced by the exam review. For question 10, the voltage output in a circuit with a dependent source is calculated to be -2 V, while a 60-ohm resistor in question 11 dissipates 15 W. The confusion arises in determining these values, particularly in understanding how the dependent source relates to the current and voltage. The calculations involve recognizing the relationship between the dependent source and the circuit parameters. Proper application of circuit laws is essential for accurate results in these scenarios.
-EquinoX-
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Homework Statement



I am reviewing an exam which is from the 2001 of my class

http://img194.imageshack.us/img194/5340/65220653.jpg
http://img194.imageshack.us/img194/12/35654148.jpg

The answer key states for no. 10 the answer is
Voltage out in circuit with dependent source is -2 V.and for no. 11 is
60-ohms resistor in single big loop dissipates 15 W

Homework Equations


The Attempt at a Solution



Problem is how do they get these numbers, the question seems to be really simple... can someone guide me
 
Last edited by a moderator:
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-EquinoX- said:

Homework Statement



I am reviewing an exam which is from the 2001 of my class

http://img191.imageshack.us/i/79549579.jpg/
http://img200.imageshack.us/i/53295341.jpg/

The answer key states for no. 10 the answer is
10mA current source (in parallel with R and dep current source) delivers 100uW

and for no. 11 is
60-ohms resistor in single big loop dissipates 15 W

Homework Equations





The Attempt at a Solution



Problem is how do they get these numbers, the question seems to be really simple... can someone guide me

The attachments didn't seem to work...
 
Last edited by a moderator:
I fixed it now.

For no. 10, my guess is that v0 is 0.04V, as 10mA has to equal to the dependent source which is 0.25v0. Is this true?

For no. 11, p = v^2/R, so why isn't it just 100^2/60
 
Last edited:
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