Cut-off frequencies, Quality for a given Transfer Function

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SUMMARY

The discussion focuses on analyzing the transfer function H(s)=10s/(s^2+300s+10^6) of an RLC band pass filter to determine the center frequency, lower and upper half power frequencies, and the quality factor Q. The participant initially struggled with the transfer function's format, suspecting it to be an active band pass filter due to the differing values of (R/L) in the numerator and denominator. Ultimately, they resolved the issue by multiplying the transfer function by (30/30), transforming it into a standard form that allowed for the extraction of the desired parameters.

PREREQUISITES
  • Understanding of RLC circuit theory
  • Familiarity with transfer functions in control systems
  • Knowledge of frequency response analysis
  • Basic skills in algebraic manipulation of equations
NEXT STEPS
  • Study the characteristics of active band pass filters
  • Learn how to derive cut-off frequencies from transfer functions
  • Explore the concept of quality factor Q in filter design
  • Investigate the implications of multiplying transfer functions for analysis
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in filter design and analysis will benefit from this discussion.

mrwest09
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Homework Statement



Given the network transfer function

H(s)=10s/(s^2+300s+10^6)

Find the center frequency, lower and upper half power frequencies and the quality factor Q.

Homework Equations



Beta=R/L

(omega naught)^2=1/(LC)

BW=hi-lo=R/L

H(s)=(R/L)s/(s^2+(R/L)s+1/(LC))

The Attempt at a Solution



Well I am truly stumped. Our prof has given us an equation for the transfer function of RLC band pass filter and the equation in the problem nearly fits the format (located above), however the value for (R/L) differs in the numerator and denominator suggesting it is an active band pass filter. However our prof has not mentioned anything about active band pass filters yet in class (I was reading ahead) and therefore I was thinking that couldn't be it.

At this point I don't even know where to begin. Should I attempt to make it fit into an active band pass filter? Or solve for the cut off frequencies by finding the magnitude of the transfer function and setting it equal to 1/sqrt(2).

I think I just need a nudge the right direction.

Thanks for any help!
 
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So I finally figured it out. Turns out if we multiply the transfer function by (30/30) we get a transfer function of
H(s)=[300s/(s^2+300s+10^6)](1/30) which fits our definition for an ideal band pass function. By simply comparing it with the format for the ideal band pass function we can determine all of the above parameters.
 

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