Cut-off frequencies, Quality for a given Transfer Function

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mrwest09
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Homework Statement



Given the network transfer function

H(s)=10s/(s^2+300s+10^6)

Find the center frequency, lower and upper half power frequencies and the quality factor Q.

Homework Equations



Beta=R/L

(omega naught)^2=1/(LC)

BW=hi-lo=R/L

H(s)=(R/L)s/(s^2+(R/L)s+1/(LC))

The Attempt at a Solution



Well I am truly stumped. Our prof has given us an equation for the transfer function of RLC band pass filter and the equation in the problem nearly fits the format (located above), however the value for (R/L) differs in the numerator and denominator suggesting it is an active band pass filter. However our prof has not mentioned anything about active band pass filters yet in class (I was reading ahead) and therefore I was thinking that couldn't be it.

At this point I don't even know where to begin. Should I attempt to make it fit into an active band pass filter? Or solve for the cut off frequencies by finding the magnitude of the transfer function and setting it equal to 1/sqrt(2).

I think I just need a nudge the right direction.

Thanks for any help!
 
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So I finally figured it out. Turns out if we multiply the transfer function by (30/30) we get a transfer function of
H(s)=[300s/(s^2+300s+10^6)](1/30) which fits our definition for an ideal band pass function. By simply comparing it with the format for the ideal band pass function we can determine all of the above parameters.