Cyclic Subgroups in Symmetric and Cyclic Groups

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Suppose K= < x > is a cyclic group with 2 elements and H= S3 is symmetric group with 6 elements. Find all different cyclic subgroups of G= H x K.

Now since K is generated by x with 2 elements, I have K= {1,x} and H= {1, (12), (13), (23), (123), (132)}

What I am confused about is finding cyclic subgroups of H x K. Am I supposed to be checking each element of H x K and seeing if it can generate the whole group?
 
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All elements of the group generate a cyclic group. Some of them generate the same cyclic group. You are just supposed to figure out how many there are. The whole group isn't cyclic.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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