Cylindrical Canister Mole Problem

In summary, the problem involves an empty cylindrical canister being filled with pure oxygen at a specific temperature and pressure for storage in a space station. The equations used to calculate the number of moles of oxygen in the canister and the increase in mass due to the gas are PV = nRT and m = nM, respectively. The canister can hold 30.2 moles of oxygen and the gas increases the mass to be lifted by 0.9644 kg.
  • #1
ryaneye
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Homework Statement



An empty cylindrical canister 1.50 m long and 94.0 cm in diameter is to be filled with pure oxygen at 30.0 C to store in a space station. To hold as much gas as possible, the absolute pressure of the oxygen will be 21.5 atm . The molar mass of oxygen is 32.0 g/mol .


Homework Equations



How many moles of oxygen does this canister hold?
For someone lifting this canister, by how many kilograms does this gas increase the mass to be lifted?

The Attempt at a Solution

 
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  • #2
1. How many moles of oxygen does this canister hold?PV = nRTn = PV/RT n = (21.5 atm)(1.50 m^3)/(8.314 J/mol K)(303.5K) n = 30.2 moles of oxygen2. For someone lifting this canister, by how many kilograms does this gas increase the mass to be lifted?m = nM m = (30.2 moles)(32.0 g/mol) m = 964.4 g m = 0.9644 kg
 
  • #3


To calculate the volume of the canister, we use the formula for the volume of a cylinder: V = πr^2h, where r is the radius (47.0 cm) and h is the height (1.50 m). This gives us a volume of 3.48 x 10^4 cm^3 or 3.48 x 10^-2 m^3.
To calculate the number of moles of oxygen, we use the ideal gas law: PV = nRT, where P is the absolute pressure (21.5 atm), V is the volume (3.48 x 10^-2 m^3), n is the number of moles (unknown), R is the gas constant (0.08206 L·atm/mol·K), and T is the temperature in Kelvin (273.15 + 30 = 303.15 K). Rearranging the equation, we get n = PV/RT = (21.5)(3.48 x 10^-2)/(0.08206)(303.15) = 2.92 moles of oxygen.
To calculate the mass of the oxygen, we use the molar mass of oxygen (32.0 g/mol) and the number of moles we calculated earlier (2.92 moles). This gives us a mass of 93.4 g.
To convert this mass to kilograms, we divide by 1000, giving us a mass of 0.0934 kg.
Therefore, the gas increases the mass of the canister by 0.0934 kg. This may seem like a small amount, but in the weightless environment of a space station, every gram counts. It is important to carefully consider the weight of all objects brought on board, including gas canisters, to ensure the safety and efficiency of the space station.
 

1. What is the "Cylindrical Canister Mole Problem"?

The "Cylindrical Canister Mole Problem" is a mathematical problem that involves determining the maximum number of moles that can fit inside a cylindrical canister of a given volume and diameter.

2. How is the maximum number of moles calculated in this problem?

The maximum number of moles is calculated using the formula V/22.4, where V is the volume of the canister in cubic centimeters. This formula assumes that each mole occupies a volume of 22.4 liters at standard temperature and pressure.

3. What are the assumptions made in solving the "Cylindrical Canister Mole Problem"?

The main assumptions made in solving this problem are that each mole occupies a fixed volume of 22.4 liters, the moles are evenly distributed within the canister, and there is no wasted space between the moles.

4. Can this problem be solved using other shapes besides a cylinder?

Yes, this problem can be solved using other shapes such as a sphere or a rectangular prism. However, the formula for calculating the maximum number of moles will differ depending on the shape of the container.

5. What applications does the "Cylindrical Canister Mole Problem" have in real life?

This problem is often used in chemistry and engineering to determine the maximum number of gas molecules that can be stored in a container of a specific size. It also has applications in packaging and storage industries where the optimal use of space is important.

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