Damped Oscillations: Mass 300 g, k=1.50 N/m, b in kg/s

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A mass of 300 g attached to a spring with a spring constant of 1.50 N/m undergoes damped oscillations, with the amplitude decreasing to 1/10 of its initial value after 28 seconds. The damping constant b needs to be calculated based on this information. The equation of motion for the system is given by x = A_0e^{-qt}sin(ωt + φ), where q relates to the damping constant. Additionally, the discussion includes inquiries about the graphical representation of mechanical and kinetic energies throughout the oscillation. Understanding these dynamics is crucial for analyzing damped harmonic motion effectively.
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A weight of mass m = 300 g hangs vertically from a spring that has a spring constant k = 1.50 N/m. The mass is set into vertical oscillation and after 28 s you find that the amplitude of the oscillation is 1/10 that of the initial amplitude. What is the damping constant b associated with the motion (in kg/s)? Also what would the graphs of the mechanical and kinetic energies look like?
 
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physicsgurl123 said:
A weight of mass m = 300 g hangs vertically from a spring that has a spring constant k = 1.50 N/m. The mass is set into vertical oscillation and after 28 s you find that the amplitude of the oscillation is 1/10 that of the initial amplitude. What is the damping constant b associated with the motion (in kg/s)? Also what would the graphs of the mechanical and kinetic energies look like?
What is the equation of motion here? Hint: The general form of solution is:

x = A_0e^{-qt}\sin(\omega t + \phi)AM
 
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