Dark fringes for single-slit diffraction

Thread starter golriz
Start date Oct 27, 2010
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Diffraction Fringes

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The discussion focuses on calculating the number of dark fringes produced in a single-slit diffraction pattern when light with a wavelength of 651 nm passes through a slit that is 5.47x10^-6 m wide. The formula used is sin(theta) = m * wavelength / w, where 'm' represents the order of the dark fringe. Participants suggest finding theta for increasing values of 'm' until the calculation is no longer valid. This approach will determine the total number of dark fringes on either side of the central maximum. The discussion emphasizes the mathematical method for deriving the dark fringe positions in the diffraction pattern.

Oct 27, 2010

golriz

How many dark fringes will be produced n either side of the central maximum if light (its wavelength is 651 nm ) is incident on a single slit that is 5.47x10^-6 m wide?

sin (theta) = m.wavelength/w

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Oct 27, 2010

Delphi51

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Looks good. Find theta when m = 1. Then for m = 2, and so on until it doesn't work anymore.

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